2x^2=(2((x-5)(x+5)))+250

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Solution for 2x^2=(2((x-5)(x+5)))+250 equation:


Simplifying
2x2 = (2((x + -5)(x + 5))) + 250

Reorder the terms:
2x2 = (2((-5 + x)(x + 5))) + 250

Reorder the terms:
2x2 = (2((-5 + x)(5 + x))) + 250

Multiply (-5 + x) * (5 + x)
2x2 = (2((-5(5 + x) + x(5 + x)))) + 250
2x2 = (2(((5 * -5 + x * -5) + x(5 + x)))) + 250
2x2 = (2(((-25 + -5x) + x(5 + x)))) + 250
2x2 = (2((-25 + -5x + (5 * x + x * x)))) + 250
2x2 = (2((-25 + -5x + (5x + x2)))) + 250

Combine like terms: -5x + 5x = 0
2x2 = (2((-25 + 0 + x2))) + 250
2x2 = (2((-25 + x2))) + 250
2x2 = ((-25 * 2 + x2 * 2)) + 250
2x2 = ((-50 + 2x2)) + 250
2x2 = (-50 + 2x2) + 250

Remove parenthesis around (-50 + 2x2)
2x2 = -50 + 2x2 + 250

Reorder the terms:
2x2 = -50 + 250 + 2x2

Combine like terms: -50 + 250 = 200
2x2 = 200 + 2x2

Add '-2x2' to each side of the equation.
2x2 + -2x2 = 200 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
0 = 200 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
0 = 200 + 0
0 = 200

Solving
0 = 200

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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